[charter]

[3.2.0]
[更精确的算角度]

OCH/mogo-och-common-module/src/main/java/com/mogo/och/common/module/utils/CoordinateCalculateRouteUtil.java

@@ -14,6 +14,7 @@ import java.util.HashMap;
 import java.util.List;
 import java.util.Map;
 
+import kotlin.Triple;
 import mogo.telematics.pad.MessagePad;
 
 /**
@@ -340,4 +341,56 @@ public class CoordinateCalculateRouteUtil {
         //弧度转角度制
         return (int) (180 * radian / Math.PI);
     }
+
+
+    private static Triple<Double,Double,Double> ball2xyz(Double thera,Double fie,Double r){
+        double x = r * Math.cos(thera) * Math.cos(fie);
+        double y = r * Math.cos(thera) * Math.sin(fie);
+        double z = r * Math.sin(thera);
+        return new Triple(x,y,z);
+    }
+
+    /**
+     * https://blog.csdn.net/reborn_lee/article/details/82497577
+     * 将地理经纬度转换成笛卡尔坐标系
+     */
+    private static Triple<Double,Double,Double>  geo2xyz(double lat,double lng){
+        double thera = (Math.PI * lat) / 180;
+        double fie = (Math.PI * lng) / 180;
+        return ball2xyz(thera, fie,6400.0);
+    }
+
+    /**
+     * 计算3个地理坐标点之间的夹角
+     * @param l1 顶点坐标
+     * @param l2
+     * @param l3
+     * @return l1为顶点的角度 精度没有angleOflocation高
+     */
+    public static double getDegree(LatLng l2,LatLng l1,LatLng l3) {
+        Triple<Double,Double,Double> p1 = geo2xyz(l1.latitude,l1.longitude);
+        Triple<Double,Double,Double> p2 = geo2xyz(l2.latitude,l2.longitude);
+        Triple<Double,Double,Double> p3 = geo2xyz(l3.latitude,l3.longitude);
+
+        double x1 = p1.getFirst();
+        double y1 = p1.getSecond();
+        double z1 = p1.getThird();
+
+        double x2 = p2.getFirst();
+        double y2 = p2.getSecond();
+        double z2 = p2.getThird();
+
+        double x3 = p3.getFirst();
+        double y3 = p3.getSecond();
+        double z3 = p3.getThird();
+
+        // 计算向量 P2P1 和 P2P3 的夹角 https://www.zybang.com/question/3379a30c0dd3041b3ef966803f0bf758.html
+        double p1P2 = Math.sqrt(Math.pow(x2 - x1,2.0) + Math.pow(y2 - y1,2.0) + Math.pow(z2 - z1,2.0));
+        double p2p3 = Math.sqrt(Math.pow(x3 - x2,2.0) + Math.pow(y3 - y2,2.0) + Math.pow(z3 - z2,2.0));
+
+        double p = (x1 - x2) * (x3 - x2) + (y1 - y2) * (y3 - y2) + (z1 - z2) * (z3 - z2); //P2P1*P2P3
+
+        return (Math.acos(p / (p1P2 * p2p3)) / Math.PI) * 180;
+    }
+
 }